QJEEM22Ch1caf: JEE Main 2022 Chemistry - Class 12 JEEM22Ch1caf Solution: In the following reaction The yield for reaction I is and that…

Let initial moles of reactant taken = n

Total moles obtained for benzene sulphonic acid (with % yield = 60%) = 0.6n


Moles of benzene sulphonic acid before reaction II = 0.6n

Moles obtained for phenol (with % yield = 50%) = 0.6 × 0.5n = 0.3n

So over all % yield of complete reaction $=\frac{0.3 \mathrm{n}}{\mathrm{n}} \times 100=30$