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QJEEM22Ch1ab3: JEE Main 2022 Chemistry - Class 12 JEEM22Ch1ab3 Solution: Hex-4-ene-2-ol on treatment with PCC gives 'A'. 'A' on reaction …

Hex-4-ene-2-ol on treatment with PCC gives 'A'. 'A' on reaction with sodium hypoiodite gives 'B', which on further heating with soda lime gives 'C'. The compound 'C' is :

Multiple Choice Options

  • A 2-pentene
  • B proponaldehyde
  • C 2-butene
  • D 4-methylpent-2-ene

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JEE Main 2022 (Online) 24th June Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 74 English Explanation

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