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QJEEM22Ch16dc: JEE Main 2022 Chemistry - Class 12 JEEM22Ch16dc Solution: A gaseous mixture of two substances A and B, under a total…

A gaseous mixture of two substances A and B, under a total pressure of 0.80.8 atm is in equilibrium with an ideal liquid solution. The mole fraction of substance A is 0.50.5 in the vapour phase and 0.20.2 in the liquid phase. The vapour pressure of pure liquid A\mathrm{A} is __________ atm. (Nearest integer)

Step-by-Step Verified Solution

Given that XA=0.2,YA=0.5,PT=0.8 atmX_{A}=0.2, Y_{A}=0.5, P_{T}=0.8 \mathrm{~atm}

We know that PA=YA×PTP_{A}=Y_{A} \times P_{T}

PA=0.5×0.8=0.4P_{A}=0.5 \times 0.8=0.4

Now PA=XA×PA∘⇒PA∘=0.40.2=2 atmP_{A}=X_{A} \times P_{A}^{\circ} \Rightarrow P_{A}^{\circ}=\frac{0.4}{0.2}=2 \mathrm{~atm}

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