QJEEM22Ch129c: JEE Main 2022 Chemistry - Class 12 JEEM22Ch129c Solution: Spin only magnetic moment of [MnBr 6 ] 4 − is _________ B.M.…

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$$\begin{array}{rl}x& =+2\\ \\ \mathrm{Mn}& =[\mathrm{Ar}]3d^{5}4s^2\\ \\ {\mathrm{Mn}}^{2+}& =[\mathrm{Ar}]3d^{5}4s^0\end{array}$$


So, number of unpaired electrons $(n)=5$

$$\begin{array}{rl}\mu & =\sqrt{n(n+2)}\\ \\ \mu & =\sqrt{5(5+2)}\\ \\ & =\sqrt{35}\\ \\ & =5.91\text{ B.M. }\\ \\ & \approx 6\text{ B.M. }\end{array}$$