QJEEM22Ch1291: JEE Main 2022 Chemistry - Class 12 JEEM22Ch1291 Solution: For a reaction, given below is the graph of ln ⁡ k vs 1 T . The …

For a reaction, given below is the graph of $$\ln k$$ vs $$\frac{1}{T}$$. The activation energy for the reaction is equal to ____________ $$\mathrm{cal}{\mathrm{mol}}^{-1}$$. (nearest integer)

(Given : $$\mathrm{R}=2\mathrm{cal}{\mathrm{K}}^{-1}{\mathrm{mol}}^{-1}$$ )