QJEEM22Ch07f2: JEE Main 2022 Chemistry - Class 11 JEEM22Ch07f2 Solution: Two elements A and B which form 0.15 moles of A 2 B and AB 3…

Let atomic weight of A = x

and atomic weight of B = y

$\therefore$ Molar mass of A₂B = 2x + y

and molar mass of AB₃ = x + 3y

Now, weight of 0.15 moles of A₂B = (2x + y) 0.15

and weight of 0.15 moles of AB₃ = (x + 3y) 0.15

Given, weight of 0.15 moles of A₂B and AB₃ are equal.

$\therefore$ (2x + y)0.15 = (x + 3y)0.15

$\Rightarrow$ x = 2y

$\Rightarrow {x \over y} = 2$

$\therefore$ Atomic weight of A is 2 times of atomic weight of B.