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QJEEM22Ch035e: JEE Main 2022 Chemistry - Class 11 JEEM22Ch035e Solution: The K sp for bismuth sulphide (Bi 2 S 3 ) is 1.08 10 73 . The…

The Ksp for bismuth sulphide (Bi2S3) is 1.08 ×\times 10 −- 73. The solubility of Bi2S3 in mol L −- 1 at 298 K is :

Multiple Choice Options

  • A 1.0 ×\times 10 −- 15
  • B 2.7 ×\times 10 −- 12
  • C 3.2 ×\times 10 −- 10
  • D 4.2 ×\times 10 −- 8

Step-by-Step Verified Solution

JEE Main 2022 (Online) 25th June Evening Shift Chemistry - Ionic Equilibrium Question 44 English Explanation

Ksp = (2s)2(3s)3 = 108s5

108s5 = 108 × 10–75

s = 1.0 × 10–15 mol/L

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