Verified Solution • 2025–26 Session moderate

QJEEM21Phfe82: JEE Main 2021 Physics - Class 12 JEEM21Phfe82 Solution: The arm PQ of a rectangular conductor is moving from x = 0 to x …

The arm PQ of a rectangular conductor is moving from x = 0 to x = 2b outwards and then inwards from x = 2b to x = 0 as shown in the figure. A uniform magnetic field perpendicular to the plane is acting from x = 0 to x = b. Identify the graph showing the variation of different quantities with distance.

JEE Main 2021 (Online) 20th July Morning Shift Physics - Electromagnetic Induction Question 73 English

Multiple Choice Options

  • A A-Flux, B-Power dissipated, C-EMF
  • B A-Flux, B-EMF, C-Power dissipated
  • C A-Power dissipated, B-Flux, C-EMF
  • D A-EMF, B-Power dissipated, C-Flux

Step-by-Step Verified Solution

As the rectangular conductor moves in field area, so flux is increasing up to x = b, then flux is generated on return journey from x = b to x = 0. The flux is shown by plot A of the graph.

As, emf, e=−dϕdte = - {{d\phi } \over {dt}} , which is shown by curve B and power dissipated, P = VI which is shown by curve C.

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