QJEEM21Phf7dd: JEE Main 2021 Physics - Class 12 JEEM21Phf7dd Solution: Figure shows a circuit that contains four identical resistors…

Given, resistance, R = 2$$\mathrm{\Omega }$$,

Inductance, L = 2 mH,

emf, E = 9 V

and i be the current.

$$\because$$ At t = 0 when switch is closed, inductors behave as open circuit.

$$\therefore$$ Effective circuit will be


By using Ohm's law, V = i R_eq

$$\Rightarrow$$ i = V/R_eq

where, R_eq is equivalent resistance of series resistors,

i.e., R_eq = R + R = 2R = 2 $$\times$$ 2 = 4 $$\mathrm{\Omega }$$

$$\therefore$$ $$i=\frac{9}{4}=2.25$$A