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QJEEM21Phecb1: JEE Main 2021 Physics - Class 12 JEEM21Phecb1 Solution: A point charge of +12 C is at a distance 6 cm vertically above…

A point charge of +12 μ\mu C is at a distance 6 cm vertically above the centre of a square of side 12 cm as shown in figure. The magnitude of the electric flux through the square will be __________ ×\times 103 Nm2/C.

JEE Main 2021 (Online) 24th February Evening Shift Physics - Electrostatics Question 141 English

Step-by-Step Verified Solution

Given, charge, q = 12 μ\mu C = 12 ×\times 10 −- 6C

Height of charge from surface, h = 6 cm = 6 ×\times 10 −- 2 m and side of square, a = 12 cm = 12 ×\times 10 −- 2 m

Using Gauss law, it is a part of cube of side 12 cm and charge at centre so;

ϕ=Q6ε0=12μc6ε0=2×4π×9×109×10−6\phi = {Q \over {6{\varepsilon _0}}} = {{12\mu c} \over {6{\varepsilon _0}}} = 2 \times 4\pi \times 9 \times {10^9} \times {10^{ - 6}}

=226×103= 226 \times {10^3} Nm2 / C

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