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QJEEM21Pheb5a: JEE Main 2021 Physics - Class 11 JEEM21Pheb5a Solution: A particle is moving with constant acceleration 'a'. Following…

A particle is moving with constant acceleration 'a'. Following graph shows v2 versus x(displacement) plot. The acceleration of the particle is ___________ m/s2.

JEE Main 2021 (Online) 31st August Evening Shift Physics - Motion in a Straight Line Question 56 English

Step-by-Step Verified Solution

y = mx + C

v2 = 2010{{20} \over {10}} x + 20

v2 = 2x + 20

2v dvdx{{dv} \over {dx}} = 2

∴\therefore a = v dvdx{{dv} \over {dx}} = 1

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