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QJEEM21Pheb0c: JEE Main 2021 Physics - Class 12 JEEM21Pheb0c Solution: The electric field in a plane electromagnetic wave is given by…

The electric field in a plane electromagnetic wave is given by

E→=200cos⁡[(0.5×103m)x−(1.5×1011rads×t)]Vmj^. If this wave falls normally on a perfectly reflecting surface having an area of 100 cm2. If the radiation pressure exerted by the E.M. wave on the surface during a 10 minute exposure is x109Nm2. Find the value of x .

Step-by-Step Verified Solution

E0 = 200

I=12ε0E02.C

Radiation pressure

P=2IC

=(2C)(12ε0E02C)

=ε0E02

=8.85×10−12×2002

=8.85×10−8×4

=354109

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