QJEEM21Phea8d: JEE Main 2021 Physics - Class 12 JEEM21Phea8d Solution: At very high frequencies, the effective impendence of the given …

At very high frequencies, the effective impendence of the given circuit will be ________________ $$\mathrm{\Omega }$$.

Step-by-Step Verified Solution

X_L = 2$$\pi$$fL

f is very large

$$\therefore$$ X_L is very large hence open circuit.

$$X_C=\frac{1}{2\pi fC}$$

f is very large.

$$\therefore$$ X_C is very small, hence short circuit.

Final circuit



$$\therefore$$ $$Z_{eq}=1+\frac{2\times 2}{2+2}=2$$