QJEEM21Phdef2: JEE Main 2021 Physics - Class 11 JEEM21Phdef2 Solution: A particle of mass m is suspended from a ceiling through a…

Question

Verified Solution • 2025–26 Session moderate

A particle of mass m is suspended from a ceiling through a string of length L. The particle moves in a horizontal circle of radius r such that

r = \frac{L}{\sqrt{2}}

. The speed of particle will be :

Accepted Answer

r = \frac{l}{\sqrt{2}}

\sin θ = \frac{r}{l} = \frac{l}{\sqrt{2}}

θ

= 45

^{\circ}

T \sin θ = \frac{m v^{2}}{r}

T \cos θ = m g

\tan θ = \frac{v^{2}}{r g} \Rightarrow v = \sqrt{r g}

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