Verified Solution • 2025–26 Session
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QJEEM21Phd948: JEE Main 2021 Physics - Class 11 JEEM21Phd948 Solution: A particle executes simple harmonic motion represented by…
A particle executes simple harmonic motion represented by displacement function as
x(t) = A sin( t + )
If the position and velocity of the particle at t = 0 s are 2 cm and 2 cm s 1 respectively, then its amplitude is cm where the value of x is _________________.
x(t) = A sin( t + )
If the position and velocity of the particle at t = 0 s are 2 cm and 2 cm s 1 respectively, then its amplitude is cm where the value of x is _________________.
Step-by-Step Verified Solution
x(t) = A sin( t + )
v(t) = A cos ( t + )
2 = A sin ...... (1)
2 = A cos ....... (2)
From (1) and (2)
tan = 1
= 45
Putting value of in equation (1),
x = 2
v(t) = A cos ( t + )
2 = A sin ...... (1)
2 = A cos ....... (2)
From (1) and (2)
tan = 1
= 45
Putting value of in equation (1),
x = 2