QJEEM21Phd506: JEE Main 2021 Physics - Class 11 JEEM21Phd506 Solution: For what value of displacement the kinetic energy and potential …

Question

Verified Solution • 2025–26 Session moderate

For what value of displacement the kinetic energy and potential energy of a simple harmonic oscillation become equal ?

Accepted Answer

KE = PE

\frac{1}{2} k (A^{2} - X^{2}) = \frac{1}{2} K X^{2}

\Rightarrow

A^{2} - X^{2} = X^{2}

\Rightarrow

2 X^{2} = A^{2}

\Rightarrow

X^{2} = \frac{A^{2}}{\sqrt{2}}

\Rightarrow

X = \pm \frac{A}{\sqrt{2}}

Step-by-Step Verified Solution