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QJEEM21Phd368: JEE Main 2021 Physics - Class 12 JEEM21Phd368 Solution: Match List I with List II. List - I List - II (a) Capacitance,…

Match List I with List II.

List - I List - II
(a) Capacitance, C (i) M1L1T−3A−1{M^1}{L^1}{T^{ - 3}}{A^{ - 1}}
(b) Permittivity of free space, ε0{\varepsilon _0} (ii) M−1L−3T4A2{M^{ - 1}}{L^{ - 3}}{T^4}{A^2}
(c) Permeability of free space, μ0{\mu _0} (iii) M−1L−2T4A2{M^{ - 1}}{L^{ - 2}}{T^4}{A^2}
(d) Electric field, E (iv) M1L1T−2A−2{M^1}{L^1}{T^{ - 2}}{A^{ - 2}}


Choose the correct answer from the options given below

Multiple Choice Options

  • A (a) →\to (iii), (b) →\to (ii), (c) →\to (iv), (d) →\to (i)
  • B (a) →\to (iii), (b) →\to (iv), (c) →\to (ii), (d) →\to (i)
  • C (a) →\to (iv), (b) →\to (ii), (c) →\to (iii), (d) →\to (i)
  • D (a) →\to (iv), (b) →\to (iii), (c) →\to (ii), (d) →\to (i)

Step-by-Step Verified Solution

q = CV

[C]=[qV]=(A×T)ML2T−2[C] = \left[ {{q \over V}} \right] = {{(A \times T)} \over {M{L^2}{T^{ - 2}}}}

=M−1L−2T4A2= {M^{ - 1}}{L^{ - 2}}{T^4}{A^2}

[E]=[Fq]=MLT−2AT[E] = \left[ {{F \over q}} \right] = {{ML{T^{ - 2}}} \over {AT}}

=MLT−3A−1= ML{T^{ - 3}}{A^{ - 1}}

F=q1q24π∈0r2F = {{{q_1}{q_2}} \over {4\pi { \in _0}{r^2}}}

[∈0]=M−1L−3T4A2[{ \in _0}] = {M^{ - 1}}{L^{ - 3}}{T^4}{A^2}

Speed of light c=1μ0∈0c = {1 \over {\sqrt {{\mu _0}{ \in _0}} }}

μ0=1∈0c2{\mu _0} = {1 \over {{ \in _0}{c^2}}}

[μ0]=1M−1L−3T4A2][LT−1]2[{\mu _0}] = {1 \over {{M^{ - 1}}{L^{ - 3}}{T^4}{A^2}]{{[L{T^{ - 1}}]}^2}}}

=[M1L1T−2A−2]= [{M^1}{L^1}{T^{ - 2}}{A^{ - 2}}]

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