QJEEM21Phcefc: JEE Main 2021 Physics - Class 12 JEEM21Phcefc Solution: First, a set of n equal resistors of 10 Ω each are connected in …

Question

Verified Solution • 2025–26 Session moderate

QJEEM21Phcefc: JEE Main 2021 Physics - Class 12 JEEM21Phcefc Solution: First, a set of n equal resistors of 10 Ω each are connected in …

First, a set of n equal resistors of 10

Ω

each are connected in series to a battery of emf 20V and internal resistance 10

Ω

. A current I is observed to flow. Then, the n resistors are connected in parallel to the same battery. It is observed that the current is increased 20 times, then the value of n is ............... .

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank

Browse year-wise authentic previous years' questions with solutions

Authentic CBT Mock Tests

Simulate official exam environment with live timer and percentile scoring

Accepted Answer

In series

R_{e q} = n R = 10 n

i_{s} = \frac{20}{10 + 10 n} = \frac{2}{1 + n}

In parallel

R_{e q} = \frac{10}{n}

i_{p} = \frac{20}{\frac{10}{n} + 10} = \frac{2 n}{1 + n}

\frac{i_{p}}{i_{s}} = 20

\frac{(\frac{2 n}{1 + n})}{(\frac{2}{1 + n})} = 20

n = 20

QJEEM21Phcefc: JEE Main 2021 Physics - Class 12 JEEM21Phcefc Solution: First, a set of n equal resistors of 10 Ω each are connected in …

Step-by-Step Verified Solution

Related Learning Resources & Exam Preparation