Verified Solution • 2025–26 Session moderate

QJEEM21Phc0b2: JEE Main 2021 Physics - Class 12 JEEM21Phc0b2 Solution: A resistor dissipates 192 J of energy in 1s when a current of…

A resistor dissipates 192 J of energy in 1s when a current of 4A is passed through it. Now, when the current is doubled, the amount of thermal energy dissipated in 5s in _________ J.

Step-by-Step Verified Solution

E = i2Rt

192 = 16 (R) (1)

R = 12Ω

E1 = (8)2 (12) (5)

= 3840 J

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring