Verified Solution • 2025–26 Session moderate

QJEEM21Phbf1f: JEE Main 2021 Physics - Class 11 JEEM21Phbf1f Solution: if the rms speed of oxygen molecules at 0 C is 160 m/s, find…

if the rms speed of oxygen molecules at 0 ∘^\circ C is 160 m/s, find the rms speed of hydrogen molecules at 0 ∘^\circ C.

Multiple Choice Options

  • A 640 m/s
  • B 40 m/s
  • C 80 m/s
  • D 332 m/s

Step-by-Step Verified Solution

Vrms=3KTM{V_{rms}} = \sqrt {{{3KT} \over M}}

(Vrms)O2(Vrms)H2=MH2MO2=232{{{{({V_{rms}})}_{{O_2}}}} \over {{{({V_{rms}})}_{{H_2}}}}} = \sqrt {{{{M_{{H_2}}}} \over {{M_{{O_2}}}}}} = \sqrt {{2 \over {32}}}

(Vrms)H2=4×(Vrms)O2{({V_{rms}})_{{H_2}}} = 4 \times {({V_{rms}})_{{O_2}}}

=4×160= 4 \times 160

=640= 640 m/s

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