Verified Solution • 2025–26 Session moderate

QJEEM21Phb1ce: JEE Main 2021 Physics - Class 12 JEEM21Phb1ce Solution: An aeroplane, with its wings spread 10 m, is flying at a speed…

An aeroplane, with its wings spread 10 m, is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth's field at that part is 2.5 × 10−4 Wb/m2 and the angle of dip is 60∘. The emf induced between the tips of the plane wings will be __________.

Multiple Choice Options

  • A 88.37 mV
  • B 62.50 mV
  • C 54.125 mV
  • D 108.25 mV

Step-by-Step Verified Solution

εind = (Bv) LV and Bv = BTotal sin60o

∴ εind = (2.5 × 10−4)(sin 60o) × 10 × 180 × 518

= 108.25 mV

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