QJEEM21Phaffc: JEE Main 2021 Physics - Class 11 JEEM21Phaffc Solution: The amplitude of wave disturbance propagating in the positive…

Question

Verified Solution • 2025–26 Session moderate

The amplitude of wave disturbance propagating in the positive x-direction is given by

y = {1 \over {{{(1 + x)}^2}}}

at time t = 0 and

y = {1 \over {1 + {{(x - 2)}^2}}}

at t = 1 s, where x and y are in metres. The shape of wave does not change during the propagation. The velocity of the wave will be ___________ m/s.

Accepted Answer

As per question,

at t = 0, y =

{1 \over {{{(1 + x)}^2}}}

and at t = 1 s, y =

{1 \over {1 + {{(x - 2)}^2}}}

.... (i)

As we know,

At t = t s, y =

{1 \over {1 + {{(x - vt)}^2}}}

So, at t = 1 s, y =

{1 \over {1 + {{(x - v)}^2}}}

.... (ii)

On comparing Eqs. (i) and (ii), we get

v = 2 ms^{$-$ 1}

Hence, the velocity of the wave will be 2 m/s.

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