QJEEM21Pha8b5: JEE Main 2021 Physics - Class 11 JEEM21Pha8b5 Solution: A soap bubble of radius 3 cm is formed inside the another soap…

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QJEEM21Pha8b5: JEE Main 2021 Physics - Class 11 JEEM21Pha8b5 Solution: A soap bubble of radius 3 cm is formed inside the another soap…

A soap bubble of radius 3 cm is formed inside the another soap bubble of radius 6 cm. The radius of an equivalent soap bubble which has the same excess pressure as inside the smaller bubble with respect to the atmospheric pressure is ................ cm.

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Accepted Answer

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Excess pressure inside the smaller soap bubble

Δ P = \frac{4 S}{r_{1}} + \frac{4 S}{r_{2}}

.... (i)

The excess pressure inside equivalent soap bubble

Δ P = \frac{4 S}{R_{e q}}

....... (ii)

From (i) & (ii)

\frac{4 S}{R_{e q}} = \frac{4 S}{r_{1}} + \frac{4 S}{r_{2}}

\frac{1}{R_{e q}} = \frac{1}{r_{1}} + \frac{1}{r_{2}}

= \frac{1}{6} + \frac{1}{3}

R_eq = 2 cm

QJEEM21Pha8b5: JEE Main 2021 Physics - Class 11 JEEM21Pha8b5 Solution: A soap bubble of radius 3 cm is formed inside the another soap…

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