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QJEEM21Pha81f: JEE Main 2021 Physics - Class 12 JEEM21Pha81f Solution: Three capacitors C 1 = 2 F, C 2 = 6 F and C 3 = 12 F are…

Three capacitors C1 = 2 μ\mu F, C2 = 6 μ\mu F and C3 = 12 μ\mu F are connected as shown in figure. Find the ratio of the charges on capacitors C1, C2 and C3 respectively :

JEE Main 2021 (Online) 27th August Evening Shift Physics - Capacitor Question 72 English

Multiple Choice Options

  • A 2:01:01
  • B 2:03:03
  • C 1:02:02
  • D 3:04:04

Step-by-Step Verified Solution

JEE Main 2021 (Online) 27th August Evening Shift Physics - Capacitor Question 72 English Explanation
(VD −- V) C2 + (VD −- 0) C3 = 0

(VD −- V) 6 + (VD −- 0) 12 = 0

VD −- V + 2VD = 0

VD = V3{V \over 3}

q2 = (V −- VD) C2 = (V−V3)\left( {V - {V \over 3}} \right) (6 μ\mu F)

q2 = (4V) μ\mu F

q3 = (VD −- 0) C3 = V3{{V \over 3}} ×\times 12 μ\mu F = 4V μ\mu F

q1 = (V −- 0) C1 = V(2 μ\mu F)

q1 : q2 : q3 = 2 : 4 : 4

q1 : q2 : q3 = 1 : 2 : 2

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