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QJEEM21Pha7e1: JEE Main 2021 Physics - Class 12 JEEM21Pha7e1 Solution: The image of an object placed in air formed by a convex…

The image of an object placed in air formed by a convex refracting surface is at a distance of 10 m behind the surface. The image is real and is at 2rd3{{{2^{rd}}} \over 3} of the distance of the object from the surface. The wavelength of light inside the surface is 23{2 \over 3} times the wavelength in air. The radius of the curved surface is x13{x \over {13}} m. The value of 'x' is ___________.

Step-by-Step Verified Solution

μ2v−μ1u=μ2−μ1R{{{\mu _2}} \over v} - {{{\mu _1}} \over u} = {{{\mu _2} - {\mu _1}} \over R}

μ1=1{\mu _1} = 1 , μ2=1.5{\mu _2} = 1.5

1.5+10−1−15=1.5−1+R{{1.5} \over { + 10}} - {1 \over { - 15}} = {{1.5 - 1} \over { + R}}

R=3013R = {{30} \over {13}} m

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