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QJEEM21Pha4cf: JEE Main 2021 Physics - Class 11 JEEM21Pha4cf Solution: A boy of mass 4 kg is standing on a piece of wood having mass 5 …

A boy of mass 4 kg is standing on a piece of wood having mass 5 kg. If the coefficient of friction between the wood and the floor is 0.5, the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is __________ N. (Round off to the Nearest Integer) [Take g = 10 ms-2 ]

JEE Main 2021 (Online) 17th March Evening Shift Physics - Laws of Motion Question 80 English

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JEE Main 2021 (Online) 17th March Evening Shift Physics - Laws of Motion Question 80 English Explanation
∵\because f = T

⇒\Rightarrow μ\mu N = T

⇒\Rightarrow μ\mu (90 −- T) = T

⇒\Rightarrow 0.5 (90 −- T) = T

⇒\Rightarrow 90 −- T = 2T

⇒\Rightarrow 3T = 90

⇒\Rightarrow T = 30 N

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