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QJEEM21Ph9e76: JEE Main 2021 Physics - Class 11 JEEM21Ph9e76 Solution: The volume V of an enclosure contains a mixture of three gases, …
The volume V of an enclosure contains a mixture of three gases, 16 g of oxygen, 28 g of nitrogen and 44 g of carbon dioxide at absolute temperature T. Consider R as universal gas constant. The pressure of the mixture of gases is :
Multiple Choice Options
- A 3RTV
- B 4RTV
- C 88RTV
- D 52RTV
Step-by-Step Verified Solution
No. of moles of O2 :
n1 = = 0.5 mole
No. of moles of N2 :
n2 = = 1 mole
No. of moles of CO2 :
n3 = = 1 mole
Total no. of moles in container : n = n1 + n2 + n3
n = 0.5 + 1 + 1 = moles
Now; PV = nRT
P =
P =
n1 =
No. of moles of N2 :
n2 =
No. of moles of CO2 :
n3 =
Total no. of moles in container : n = n1 + n2 + n3
Now; PV = nRT