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QJEEM21Ph9b8b: JEE Main 2021 Physics - Class 11 JEEM21Ph9b8b Solution: A rod CD of thermal resistance 10.0 KW − 1 is joined at the…

A rod CD of thermal resistance 10.0 KW−1 is joined at the middle of an identical rod AB as shown in figure. The end A, B and D are maintained at 200∘C, 100∘C and 125∘C respectively. The heat current in CD is P watt. The value of P is ................. .

JEE Main 2021 (Online) 27th August Morning Shift Physics - Heat and Thermodynamics Question 196 English

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Rods are identical so

RAB = RCD = 10 Kw−1

C is mid-point of AB, so

RAC = RCB = 5 Kw−1

at point C

200−T5=T−12510+T−1005

2(200 − T) = T − 125 + 2(T − 100)

400 − 2T = T − 125 + 2T − 200

T=7255 = 145∘C

Ih=145−12510w=2010w

Ih = 2wJEE Main 2021 (Online) 27th August Morning Shift Physics - Heat and Thermodynamics Question 196 English Explanation

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