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QJEEM21Ph9129: JEE Main 2021 Physics - Class 12 JEEM21Ph9129 Solution: In the figure given, the electric current flowing through the 5 …

In the figure given, the electric current flowing through the 5 k Ω\Omega resistor is 'x' mA.

JEE Main 2021 (Online) 16th March Morning Shift Physics - Current Electricity Question 198 English
The value of x to the nearest integer is ____________.

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JEE Main 2021 (Online) 16th March Morning Shift Physics - Current Electricity Question 198 English Explanation
I=215+1+1I = {{21} \over {5 + 1 + 1}}

∴\therefore I = 3 mA

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