Verified Solution • 2025–26 Session moderate

QJEEM21Ph8c92: JEE Main 2021 Physics - Class 11 JEEM21Ph8c92 Solution: Consider two satellites S 1 and S 2 with periods of revolution…

Consider two satellites S1 and S2 with periods of revolution 1 hr. and 8 hr. respectively revolving around a planet in circular orbits. The ratio of angular velocity of satellite S1 to the angular velocity of satellite S2 is :

Multiple Choice Options

  • A 1:04
  • B 8:01
  • C 2:01
  • D 1:08

Step-by-Step Verified Solution

Given, period of revolution of first satellite,

T1 = 1h

Period of revolution of second satellite,

T2 = 8h

∴\therefore T1T2=18{{{T_1}} \over {{T_2}}} = {1 \over 8}

We know that, ω=2πT\omega = {{2\pi } \over T}

⇒ω∝1T\Rightarrow \omega \propto {1 \over T}

∵\because ω1ω2=T2T1⇒ω1ω2=81{{{\omega _1}} \over {{\omega _2}}} = {{{T_2}} \over {{T_1}}} \Rightarrow {{{\omega _1}} \over {{\omega _2}}} = {8 \over 1}

or ω1:ω2=8:1{\omega _1}:{\omega _2} = 8:1

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