Verified Solution • 2025–26 Session moderate

QJEEM21Ph8bf9: JEE Main 2021 Physics - Class 12 JEEM21Ph8bf9 Solution: The resistance of a conductor at 15 C is 16 and at 100 C is 20…

The resistance of a conductor at 15 ∘^\circ C is 16 Ω\Omega and at 100 ∘^\circ C is 20 Ω\Omega . What will be the temperature coefficient of resistance of the conductor?

Multiple Choice Options

  • A 0.010 ∘^\circ C −- 1
  • B 0.033 ∘^\circ C −- 1
  • C 0.003 ∘^\circ C −- 1
  • D 0.042 ∘^\circ C −- 1

Step-by-Step Verified Solution

16 = R0 [1 + α\alpha (15 −- T0)]

20 = R0 [1 + α\alpha (100 −- T0)]

Assuming T0 = 0 ∘^\circ C, as a general convention.

⇒\Rightarrow 1620=1+α×151+α×100{{16} \over {20}} = {{1 + \alpha \times 15} \over {1 + \alpha \times 100}}

⇒\Rightarrow α\alpha = 0.003 ∘^\circ C −- 1

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