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QJEEM21Ph86d2: JEE Main 2021 Physics - Class 12 JEEM21Ph86d2 Solution: The voltage drop across 15 resistance in the given figure will…

The voltage drop across 15 Ω\Omega resistance in the given figure will be ______________ V.

JEE Main 2021 (Online) 31st August Morning Shift Physics - Current Electricity Question 163 English

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JEE Main 2021 (Online) 31st August Morning Shift Physics - Current Electricity Question 163 English Explanation 1

⇒\Rightarrow effective circuit diagram will be

JEE Main 2021 (Online) 31st August Morning Shift Physics - Current Electricity Question 163 English Explanation 2JEE Main 2021 (Online) 31st August Morning Shift Physics - Current Electricity Question 163 English Explanation 3

Point drop across 6 Ω\Omega = 1 ×\times 6 = 6 = VAB

⇒\Rightarrow Hence point drop across 15 Ω\Omega = 6 volt = VAB

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