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QJEEM21Ph85f4: JEE Main 2021 Physics - Class 11 JEEM21Ph85f4 Solution: The resistance R = , where V = (50 2)V and I = (20 0.2)A. The…

The resistance R = VI{V \over I} , where V = (50 ±\pm 2)V and I = (20 ±\pm 0.2)A. The percentage error in R is 'x'%. The value of 'x' to the nearest integer is _________.

Step-by-Step Verified Solution

R=VIR = {V \over I}

ΔRR×100=ΔVV×100+ΔII×100{{\Delta R} \over R} \times 100 = {{\Delta V} \over V} \times 100 + {{\Delta I} \over I} \times 100

% error in R=250×100+0.220×100R = {2 \over {50}} \times 100 + {{0.2} \over {20}} \times 100

% error in R = 4 + 1

∴\therefore % error in R = 5%

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