QJEEM21Ph7f8e: JEE Main 2021 Physics - Class 12 JEEM21Ph7f8e Solution: The value of power dissipated across the zener diode (V z =…

Question

Verified Solution • 2025–26 Session moderate

The value of power dissipated across the zener diode (V_z = 15V) connected in the circuit as shown in the figure is x

\times

10^{$-$ 1} watt.

JEE Main 2021 (Online) 16th March Morning Shift Physics - Semiconductor Question 117 English

The value of x, to the nearest integer, is __________.

Accepted Answer

i = {7 \over {35}} = {1 \over 5}A

{i_1} = {{15} \over {90}} = {1 \over 6}A

{i_2} = i - {i_1}

{i_2} = {1 \over 5} - {1 \over 6}

{i_2} = {1 \over {30}}A

Power across diode; P = V₂ i₂

P = 15 \times {1 \over {30}}

P = 0.5 W

\therefore

P = 5

\times

10^{$-$ 1} W

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