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QJEEM21Ph7d6f: JEE Main 2021 Physics - Class 12 JEEM21Ph7d6f Solution: A plane electromagnetic wave of frequency 500 MHz is travelling …

A plane electromagnetic wave of frequency 500 MHz is travelling in vacuum along y-direction. At a particular point in space and time,
B→ = 8.0 × 10−8 z^T. The value of electric field at this point is :

(speed of light = 3 × 108 ms−1)

x^, y^, z^ are unit vectors along x, y and z directions.

Multiple Choice Options

  • A 2.6 x^ V/m
  • B −24 x^ V/m
  • C 24 x^ V/m
  • D −2.6 y^ V/m

Step-by-Step Verified Solution

E0=B.C

E0=(8×10−8)×(3×108)

⇒E0=24

Direction of wave travelling is in E→×B→

So, (−x^)×z^=+y^

∴ E^=−24x^ V/m

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