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QJEEM21Ph7580: JEE Main 2021 Physics - Class 11 JEEM21Ph7580 Solution: The maximum and minimum distances of a comet from the Sun are…

The maximum and minimum distances of a comet from the Sun are 1.6 ×\times 1012 m and 8.0 ×\times 1010 m respectively. If the speed of the comet at the nearest point is 6 ×\times 104 ms −- 1, the speed at the farthest point is :

Multiple Choice Options

  • A 3.0 ×\times 103 m/s
  • B 6.0 ×\times 103 m/s
  • C 1.5 ×\times 103 m/s
  • D 4.5 ×\times 103 m/s

Step-by-Step Verified Solution

JEE Main 2021 (Online) 16th March Morning Shift Physics - Gravitation Question 119 English Explanation
v1 = 6 ×\times 104 m/s

Let point 1 is nearest point,

and point 2 is farthest point.

Given, r1 = 8 ×\times 1010 m & r2 = 1.6 ×\times 1012 m

By angular momentum conservation

L1 = L2

mr1v1 = mr2v2

⇒\Rightarrow v2 = r1v1r2{{{r_1}{v_1}} \over {{r_2}}}

∴\therefore v2 = 8×1010×6×1041.6×1012{{8 \times {{10}^{10}} \times 6 \times {{10}^4}} \over {1.6 \times {{10}^{12}}}}

⇒\Rightarrow v2 = 3.0 ×\times 103 m/s

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