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QJEEM21Ph752e: JEE Main 2021 Physics - Class 11 JEEM21Ph752e Solution: If the velocity of a body related to displacement x is given by …

If the velocity of a body related to displacement x is given by υ=5000+24x m/s, then the acceleration of the body is .................... m/s2.

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V=5000+24x

dVdx=125000+24x×24=125000+24x

Now, a=VdVdx

=5000+24x×125000+24x

a = 12 m/s2

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