Verified Solution • 2025–26 Session moderate

QJEEM21Ph699c: JEE Main 2021 Physics - Class 12 JEEM21Ph699c Solution: Electric field in a plane electromagnetic wave is given by E =…

Electric field in a plane electromagnetic wave is given by E = 50 sin(500x −- 10 ×\times 1010 t) V/m The velocity of electromagnetic wave in this medium is :

(Given C = speed of light in vacuum)

Multiple Choice Options

  • A 32{3 \over 2} C
  • B C
  • C 23{2 \over 3} C
  • D C2{C \over 2}

Step-by-Step Verified Solution

V=ωK=10×1010500=2×108V = {\omega \over K} = {{10 \times {{10}^{10}}} \over {500}} = 2 \times {10^8}

V=2C3V = {{2C} \over 3} .

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