Verified Solution • 2025–26 Session moderate

QJEEM21Ph662a: JEE Main 2021 Physics - Class 11 JEEM21Ph662a Solution: A scooter accelerates from rest for time t 1 at constant rate a …

A scooter accelerates from rest for time t1 at constant rate a1 and then retards at constant rate a2 for time t2 and comes to rest. The correct value of t1t2{{{t_1}} \over {{t_2}}} wil be :

Multiple Choice Options

  • A a1+a2a2{{{a_1} + {a_2}} \over {{a_2}}}
  • B a1+a2a1{{{a_1} + {a_2}} \over {{a_1}}}
  • C a2a1{{{a_2}} \over {{a_1}}}
  • D a1a2{{{a_1}} \over {{a_2}}}

Step-by-Step Verified Solution

JEE Main 2021 (Online) 26th February Evening Shift Physics - Motion in a Straight Line Question 72 English Explanation
From given information :

For 1st interval

a1=v0t1{a_1} = {{{v_0}} \over {{t_1}}}

v0 = a1 t1 ....... (1)

For 2nd interval

a2=v0t2{a_2} = {{{v_0}} \over {{t_2}}}

v0 = a2 t2 ..... (2)

from (1) & (2)

a1 t1 = a2 t2

t1t2=a2a1{{{t_1}} \over {{t_2}}} = {{{a_2}} \over {{a_1}}}

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