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QJEEM21Ph4f1f: JEE Main 2021 Physics - Class 11 JEEM21Ph4f1f Solution: When two soap bubbles of radii a and b (b > a) coalesce, the…

When two soap bubbles of radii a and b (b > a) coalesce, the radius of curvature of common surface is :

Multiple Choice Options

  • A b−aab{{b - a} \over {ab}}
  • B a+bab{{a + b} \over {ab}}
  • C aba+b{{ab} \over {a + b}}
  • D abb−a{{ab} \over {b - a}}

Step-by-Step Verified Solution

JEE Main 2021 (Online) 17th March Morning Shift Physics - Properties of Matter Question 175 English Explanation

P1−P0=4Sb{P_1} - {P_0} = {{4S} \over b} ....(1)

P2−P0−4Sa{P_2} - {P_0} - {{4S} \over a} .....(2)

P2−P1=4SR{P_2} - {P_1} = {{4S} \over R} ......(3)

eq(2) - eq(1) = eq(3)

⇒\Rightarrow 1a−1b=1R{1 \over a} - {1 \over b} = {1 \over R}

∴\therefore R=abb−aR = {{ab} \over {b - a}}

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