Verified Solution • 2025–26 Session moderate

QJEEM21Ph4e29: JEE Main 2021 Physics - Class 12 JEEM21Ph4e29 Solution: The wavelength of the photon emitted by a hydrogen atom when an …

The wavelength of the photon emitted by a hydrogen atom when an electron makes a transition from n = 2 to n = 1 state is :

Multiple Choice Options

  • A 194.8 nm
  • B 490.7 nm
  • C 913.3 nm
  • D 121.8 nm

Step-by-Step Verified Solution

Δ\Delta E = 10.2 eV

hcλ{{hc} \over \lambda } = 10.2 eV

λ\lambda = hc(10.2)e{{hc} \over {(10.2)e}}

= 1240010.2Ao{{12400} \over {10.2}}\mathop A\limits^o

= 121.56 nm

≃\simeq 121.8 nm

Related Learning Resources & Exam Preparation