Verified Solution • 2025–26 Session moderate

QJEEM21Ph4c94: JEE Main 2021 Physics - Class 11 JEEM21Ph4c94 Solution: The minimum and maximum distances of a planet revolving around…

The minimum and maximum distances of a planet revolving around the sun are x1 and x2. If the minimum speed of the planet on its trajectory is v0 then its maximum speed will be :

Multiple Choice Options

  • A v0x12x22{{{v_0}x_1^2} \over {x_2^2}}
  • B v0x22x12{{{v_0}x_2^2} \over {x_1^2}}
  • C v0x1x2{{{v_0}x_1^{}} \over {x_2^{}}}
  • D v0x2x1{{{v_0}x_2^{}} \over {x_1^{}}}

Step-by-Step Verified Solution

Angular momentum conservation equation v0x2=v1x1{v_0}{x_2} = {v_1}{x_1}

v1=v0x2x1{v_1} = {{{v_0}{x_2}} \over {{x_1}}}

Related Learning Resources & Exam Preparation