Verified Solution • 2025–26 Session moderate

QJEEM21Ph4842: JEE Main 2021 Physics - Class 11 JEEM21Ph4842 Solution: A cylindrical container of volume 4.0 10 3 m 3 contains one…

A cylindrical container of volume 4.0 ×\times 10 −- 3 m3 contains one mole of hydrogen and two moles of carbon dioxide. Assume the temperature of the mixture is 400 K. The pressure of the mixture of gases is :

[Take gas constant as 8.3 J mol −- 1 K −- 1]

Multiple Choice Options

  • A 249 ×\times 101 Pa
  • B 24.9 ×\times 103 Pa
  • C 24.9 ×\times 105 Pa
  • D 24.9 Pa

Step-by-Step Verified Solution

V = 4 ×\times 10 −- 3 m3

n = 3 moles

T = 400 K

PV = nRT ⇒\Rightarrow P = nRTV{{nRT} \over V}

P = 3×8.3×4004×10−3{{3 \times 8.3 \times 400} \over {4 \times {{10}^{ - 3}}}}

= 24.9 ×\times 105 Pa

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