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QJEEM21Ph3b8c: JEE Main 2021 Physics - Class 12 JEEM21Ph3b8c Solution: For changing the capacitance of a given parallel plate…

For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 34d, where 'd' is the separation between the plates of parallel plate capacitor. The new capacitance (C') in terms of original capacitance (C0) is given by the following relation :

Multiple Choice Options

  • A C′=3+K4KC0
  • B C′=4+K3C0
  • C C′=4KK+3C0
  • D C′=43+KC0

Step-by-Step Verified Solution

JEE Main 2021 (Online) 16th March Morning Shift Physics - Capacitor Question 89 English Explanation
C0=∈0Ad

∴ 1C′=1C1+1C2

1C′=(3d/4)∈0KA+(d/4)∈0A

1C′=d4∈0A(3+KK)

∴ C′=4K(K+3)C0

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