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QJEEM21Ph3adc: JEE Main 2021 Physics - Class 11 JEEM21Ph3adc Solution: The velocity-displacement graph describing the motion of…

The velocity-displacement graph describing the motion of bicycle is shown in the figure.

JEE Main 2021 (Online) 16th March Morning Shift Physics - Motion in a Straight Line Question 71 English
The acceleration-displacement graph of the bicycle's motion is best described by :

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/65988e4477b28530bbd03211bd808a4faf991ce1ece8a73ffb57096cd8eed1d4.webp
  • B https://ik.imagekit.io/novatra/photos/08cd6a073b499dbbb54c37a9801c22d5aa5562ced5c1e4c65e015e24a4a8274f.webp
  • C https://ik.imagekit.io/novatra/photos/36e53416058ede4e69653eb4d5fa6c53eb909b37511b2c91f904dacec59cdd20.webp
  • D https://ik.imagekit.io/novatra/photos/874690787ecb552297e32e5c4a865c4a449bdbd486ed047cbca35409b2373d0c.webp

Step-by-Step Verified Solution

We know that, a=vdvdxa = v{{dv} \over {dx}}

as slope is constant, so a ∝\propto v (from x = 0 to 200 m)

& slope = 0 so a = 0 (from x = 200 to 400 m)

∴\therefore JEE Main 2021 (Online) 16th March Morning Shift Physics - Motion in a Straight Line Question 71 English Explanation

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