Verified Solution • 2025–26 Session moderate

QJEEM21Ph2660: JEE Main 2021 Physics - Class 11 JEEM21Ph2660 Solution: Consider two identical springs each of spring constant k and…

Consider two identical springs each of spring constant k and negligible mass compared to the mass M as shown. Fig. 1 shows one of them and Fig. 2 shows their series combination. The ratios of time period of oscillation of the two SHM is Tb/Ta = x\sqrt x , where value of x is ___________. (Round off to the Nearest Integer)

JEE Main 2021 (Online) 17th March Morning Shift Physics - Simple Harmonic Motion Question 84 English

Step-by-Step Verified Solution

Ta=2πMk{T_a} = 2\pi \sqrt {{M \over k}}

Keqseries=k1k2k1+k2=k2{K_{e{q_{series}}}} = {{{k_1}{k_2}} \over {{k_1} + {k_2}}} = {k \over 2}

Tb=2πMk/2=2π2Mk{T_b} = 2\pi \sqrt {{M \over {k/2}}} = 2\pi \sqrt {{{2M} \over k}}

Tb=2Ta{T_b} = \sqrt 2 {T_a}

TbTa=2{{{T_b}} \over {{T_a}}} = \sqrt 2

∴\therefore x = 2

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring