Verified Solution • 2025–26 Session moderate

QJEEM21Ph2336: JEE Main 2021 Physics - Class 11 JEEM21Ph2336 Solution: Moment of inertia (M. I.) of four bodies, having same mass and…

Moment of inertia (M. I.) of four bodies, having same mass and radius, are reported as;

I1 = M.I. of thin circular ring about its diameter,

I2 = M.I. of circular disc about an axis perpendicular to disc and going through the centre,

I3 = M.I. of solid cylinder about its axis and

I4 = M.I. of solid sphere about its diameter.

Then :

Multiple Choice Options

  • A I1 = I2 = I3 > I4
  • B I1 + I3 < I2 + I4
  • C I1 = I2 = I3 < I4
  • D I1 + I2 = I3 + 52{5 \over 2} I4

Step-by-Step Verified Solution

Let M and R be the mass and radius of four bodies. Then, as per question, their moment of inertia are

I1 = MR22{{M{R^2}} \over 2} ,

I2 = MR22{{M{R^2}} \over 2} ,

I3 = MR22{{M{R^2}} \over 2} ,

I4 = 25MR2{2 \over 5}M{R^2}

∴\therefore I1 = I2 = I3 > I4

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