Verified Solution • 2025–26 Session moderate

QJEEM21Ph1dd2: JEE Main 2021 Physics - Class 12 JEEM21Ph1dd2 Solution: The material filled between the plates of a parallel plate…

The material filled between the plates of a parallel plate capacitor has resistivity 200 Ω\Omega m. The value of capacitance of the capacitor is 2 pF. If a potential difference of 40 V is applied across the plates of the capacitor, then the value of leakage current flowing out of the capacitor is : (given the value of relative permittivity of material is 50)

Multiple Choice Options

  • A 9.0 μ\mu A
  • B 9.0 mA
  • C 0.9 mA
  • D 0.9 μ\mu A

Step-by-Step Verified Solution

ρ\rho = 200 Ω\Omega m

C = 2 ×\times 10 −- 12 F

V = 40 V

K = 56

i=qρkε0=q0ρkε0e−tρkε0i = {q \over {\rho k{\varepsilon _0}}} = {{{q_0}} \over {\rho k{\varepsilon _0}}}{e^{ - {t \over {\rho k{\varepsilon _0}}}}}

imax⁡=2×10−12×40200×50×8.85×10−12{i_{\max }} = {{2 \times {{10}^{ - 12}} \times 40} \over {200 \times 50 \times 8.85 \times {{10}^{ - 12}}}}

=80104×8.85= {{80} \over {{{10}^4} \times 8.85}} = 903 μ\mu A = 0.9 mA

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