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QJEEM21Ph1791: JEE Main 2021 Physics - Class 12 JEEM21Ph1791 Solution: A 16 Ω wire is bend to form a square loop. A 9V supply having…

A 16 Ω wire is bend to form a square loop. A 9V supply having internal resistance of 1Ω is connected across one of its sides. The potential drop across the diagonals of the square loop is _______________ × 10−1 V

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Here assume current as

JEE Main 2021 (Online) 25th July Evening Shift Physics - Current Electricity Question 180 English Explanation

By KVL in outer loop

9 − 12i − 4i = 0

16i = 9

8i = 92 = 4.5

= 45 × 10-1

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