QJEEM21Ph1763: JEE Main 2021 Physics - Class 11 JEEM21Ph1763 Solution: A solid disc of radius 20 cm and mass 10 kg is rotating with an …

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QJEEM21Ph1763: JEE Main 2021 Physics - Class 11 JEEM21Ph1763 Solution: A solid disc of radius 20 cm and mass 10 kg is rotating with an …

A solid disc of radius 20 cm and mass 10 kg is rotating with an angular velocity of 600 rpm, about an axis normal to its circular plane and passing through its centre of mass. The retarding torque required to bring the disc at rest in 10 s is ____________

π

\times

10^{$-$ 1} Nm.

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Accepted Answer

τ = \frac{Δ L}{Δ t} = \frac{I (ω_{f} - ω_{i})}{Δ t}

τ = \frac{\frac{m R^{2}}{2} \times [0 - ω]}{Δ t}

= \frac{10 \times {(20 \times 10^{- 2})}^{2}}{2} \times \frac{600 \times π}{30 \times 10}

= 0.4 π = 4 π \times 10^{- 2}

QJEEM21Ph1763: JEE Main 2021 Physics - Class 11 JEEM21Ph1763 Solution: A solid disc of radius 20 cm and mass 10 kg is rotating with an …

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